Soup can problem

The problem is quiet tricky, I uses the following pictures and dimensions from the internet to get the estimation of the bicycle, actual tomato soup can to find the solution of this problem.

I took the dimensions of the bicycle, which is below.

         

As it is clear from the figure Stand over height of cycle is 27” inches, therefore diameter of the back wheel = 27”-0.50”=26.50”(approximately)

 Also diameter of front wheel=24” that means its radius =24”/2= 12” 

     Similarly, Radius of back wheel = 26.50”/2 =13.25” 

  

 Therefore, finally we got the length of the bicycle

= Radius of back wheel +wheel base +radius of front wheel                

=13.25”+38”+12”

=63.25”

Moreover, Height of the bicycle is approximately =Stand over height +3”=27”+3”=30”

 

When I measure the length of the bicycle and length of the soup  (water tank) from the picture then the length of the soup can is approximately 3 times the length of the bicycle

 Hence, as the length of the bicycle is 63.25”, length of the actual soup cane (water tank ) is 3 times of 63.25=  189.75”

Again,when I measure the height of the bicycle and diameter of the soup (water tank) from the picture then the diameter of the soup (water tank) is double the height of the bicycle 

Hence, If the height of the bicycle is 30” as we found above, then the diameter of the water tank is 2 times of 30”=60” or its radius is 60”/2=30”   

  Therefore from above I can concluded that the Campbell’s soup water tank container’s height is 189.25”,and its radius is 60”

The volume of Campbell’s soup water tank  container =22/7*R*R*H

                  = 22/7*30*30*189.25 

                  =535,307.143 (cubic inch)

 As 1 cubic inch= 16.3870640693g

Hence, the above volume=535,307.143 *16.3870640693 g =8772112.449094937g

In case I have to find the relation ship between the numbers of actual soup can and the capacity of the above water tank (soup) can, then the procedure is as follows

 I am taking an example below to get the volume of actual soup container

In this case the volume of soup container = 305 g

.

Let us assume that X number of soup container were needed to fill the above container

 Therefore number of actual soup container I=8772112.449094937g /305g 

                                                                        =28761.025 approximately

                                                                        =28761 number of cans